Which Line Segments Of A Triangle Do You Draw To Find The Centroid Of A Triangle?
Centroid of a Triangle
This page shows how to construct the centroid of a triangle with compass and straightedge or ruler. The centroid of a triangle is the point where its medians intersect. Information technology works past amalgam the perpendicular bisectors of any ii sides to discover their midpoints. Then the medians are drawn, which intersect at the centroid. This structure assumes you lot are already familiar with Amalgam the Perpendicular Bisector of a Line Segment.
Printable stride-by-pace instructions
The above animation is available as a printable step-past-step educational activity sheet, which can be used for making handouts or when a computer is non available.
Proof
The image below is the final drawing from the higher up blitheness.
| Argument | Reason | |
|---|---|---|
| 1 | S is the midpoint of PQ | S was found by constructing the perpendicular bisector of PQ. See Constructing the perpendicular bisector of a segment for the method and proof |
| 2 | RS is a median of the triangle PQR | A median is a line from a vertex to the midpoint of the opposite side. See Median of a triangle. |
| 3 | Similarly, PT is a median of the triangle PQR | Every bit in (1), (2). |
| 4 | C is the centroid of the triangle PQR | The centroid of a triangle is the point where its medians intersect. See Centroid of a triangle. |
- Q.Due east.D
Attempt it yourself
Click hither for a printable worksheet containing centroid construction issues. When y'all get to the folio, utilise the browser print command to impress as many as you wish. The printed output is not copyright.Other constructions pages on this site
- List of printable constructions worksheets
Lines
- Introduction to constructions
- Copy a line segment
- Sum of n line segments
- Difference of two line segments
- Perpendicular bisector of a line segment
- Perpendicular at a point on a line
- Perpendicular from a line through a point
- Perpendicular from endpoint of a ray
- Divide a segment into n equal parts
- Parallel line through a indicate (bending re-create)
- Parallel line through a indicate (rhombus)
- Parallel line through a betoken (translation)
Angles
- Bisecting an bending
- Copy an angle
- Construct a 30° angle
- Construct a 45° angle
- Construct a 60° angle
- Construct a 90° angle (right angle)
- Sum of n angles
- Departure of 2 angles
- Supplementary angle
- Complementary bending
- Constructing 75° 105° 120° 135° 150° angles and more
Triangles
- Re-create a triangle
- Isosceles triangle, given base and side
- Isosceles triangle, given base and distance
- Isosceles triangle, given leg and apex angle
- Equilateral triangle
- 30-60-90 triangle, given the hypotenuse
- Triangle, given 3 sides (sss)
- Triangle, given one side and side by side angles (asa)
- Triangle, given two angles and not-included side (aas)
- Triangle, given two sides and included bending (sas)
- Triangle medians
- Triangle midsegment
- Triangle distance
- Triangle distance (outside example)
Right triangles
- Right Triangle, given i leg and hypotenuse (HL)
- Correct Triangle, given both legs (LL)
- Correct Triangle, given hypotenuse and one angle (HA)
- Right Triangle, given i leg and one angle (LA)
Triangle Centers
- Triangle incenter
- Triangle circumcenter
- Triangle orthocenter
- Triangle centroid
Circles, Arcs and Ellipses
- Finding the center of a circle
- Circle given 3 points
- Tangent at a point on the circumvolve
- Tangents through an external point
- Tangents to two circles (external)
- Tangents to two circles (internal)
- Incircle of a triangle
- Focus points of a given ellipse
- Circumcircle of a triangle
Polygons
- Square given i side
- Square inscribed in a circle
- Hexagon given one side
- Hexagon inscribed in a given circumvolve
- Pentagon inscribed in a given circumvolve
Non-Euclidean constructions
- Construct an ellipse with string and pins
- Discover the center of a circle with any correct-angled object
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